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Form 4 maths

Equations of straight lines

How to find the equation of a straight line from a point and a slope or from two points, and how to read the general form Ax + By + C = 0. It is used in loci, circles and most coordinate geometry questions.

What you will learn

  • 10.1 Find the equation of a line from:
  • 10.1 Read the features of a line from its equation: slope, intercepts, whether it passes through a point. Slope and inclination (slope = tan θ). The normal form is not required.
  • 10.2 Number of intersection points of two lines (0, 1, or infinitely many) from their equations.

You need first: Coordinates, Number and algebra basics

Key terms

English中文
equation of a straight line直線的方程
point-slope form點斜式
two-point form兩點式
slope-intercept form斜截式
general form一般式
inclination傾角
point of intersection交點

Standard steps

Find the equation

  1. Get the slope m (given, or from two points: m = (y₂ − y₁)/(x₂ − x₁); parallel → same m; perpendicular → −1/m).
  2. Get one point (x₁, y₁) on the line.
  3. Point-slope form: y − y₁ = m(x − x₁).
  4. Tidy into the form the question wants:
    • y = mx + c, or
    • general form Ax + By + C = 0, usually with integer coefficients and A > 0.

Read the line Ax + By + C = 0

FeatureFormula
slope−A/B
y-intercept−C/B (put x = 0)
x-intercept−C/A (put y = 0)

Safer: put x = 0 and y = 0 yourself rather than memorising.

Two lines

  1. Compare slopes:
    • different slopes → exactly one intersection;
    • same slope, different intercepts → parallel, no intersection;
    • same line → infinitely many.
  2. To find the intersection, solve the two equations simultaneously.

Does a point lie on the line?

  1. Substitute the point's x and y into the equation.
  2. Work out both sides.
  3. If they are equal, the point lies on the line; if not, it does not.

Worked examples

Example 1: The line through (2, −1) with slope 3.
y − (−1) = 3(x − 2)
y + 1 = 3x − 6
y = 3x − 7
Example 2: The line through A(−1, 4) and B(3, −4).
m = (−4 − 4)/(3 − (−1)) = −8/4 = −2
y − 4 = −2(x + 1)
y = −2x + 2
Example 3: Slope and intercepts of 3x − 4y + 12 = 0.
slope = −3/(−4) = 3/4
x = 0: −4y + 12 = 0, y-intercept 3
y = 0: 3x + 12 = 0, x-intercept −4
Example 4: The line L passes through (4, 1) and is perpendicular to 2x + y − 5 = 0. Find L and where the two lines meet.
slope of 2x + y − 5 = 0 is −2, so slope of L = 1/2
y − 1 = ½(x − 4)
2y − 2 = x − 4
L: x − 2y − 2 = 0

solve 2x + y = 5 and x − 2y = 2:
x = 12/5, y = 1/5      intersection (12/5, 1/5)
Example 5: Does a point lie on the line 3x − 4y + 6 = 0: test (2, 3) and (1, 2).
(2, 3):  3(2) − 4(3) + 6 = 6 − 12 + 6 = 0     ✓ lies on the line
(1, 2):  3(1) − 4(2) + 6 = 3 − 8 + 6 = 1 ≠ 0  ✗ does not

Common mistakes

  • Using the slope of a line as the slope of the line perpendicular to it.
  • Slope of Ax + By + C = 0 written as A/B (the sign is wrong).
  • Leaving fractions in the general form; multiply through.
  • Mixing up the x- and y-intercepts.
  • Treating "same slope" as "same line".

How the DSE tests it

  • A(2): the equation of a perpendicular bisector (a locus) and the area of a figure.
  • Section B: lines combined with circles, triangle centres, or a moving point.
  • Paper 2: match a line's equation to its graph, using the signs of slope and intercepts.

Questions you might not ask in class

Which form should my final answer be in?

Whatever the question asks. If it doesn't say, the general form Ax + By + C = 0 is safe.

Why is slope −A/B?

Rearrange Ax + By + C = 0 to y = (−A/B)x − C/B. The number in front of x is the slope.

What is the 'inclination'?

The angle the line makes with the positive x-axis, measured anticlockwise. Its tan is the slope.

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