Trigonometry in 3-D
How to find lengths and angles in 3-D figures, including the angle between a line and a plane and between two planes. The NF part is one of the hardest long-question topics; the theorem of three perpendiculars is in the syllabus from DSE 2026.
What you will learn
- 14.6 Projection of a point or line onto a plane.
- 14.7 The angle between a line and a plane; the angle between two planes; inclination.
- 14.8 The theorem of three perpendiculars.
- 14.9 2-D and 3-D problems: angles between two lines, a line and a plane, two planes; distances between points, from a point to a line, and from a point to a plane.
You need first: Trigonometry, Trigonometry (2-D), Geometry and data basics, Arcs, sectors and mensuration
Key terms
| English | 中文 |
|---|---|
| projection | 投影 |
| angle between a line and a plane | 直線與平面的交角 |
| angle between two planes | 兩平面的交角 |
| line of intersection | 交線 |
| inclination | 傾角 |
| theorem of three perpendiculars | 三垂線定理 |
| space diagonal | 空間對角線 |
Standard steps
Angle between a line and a plane
- From a point P on the line, drop a perpendicular to the plane, meeting it at N (N is the projection of P).
- Join N to the point A where the line meets the plane.
- The angle is ∠PAN, in the right-angled triangle PAN.
Angle between two planes
- Find the line of intersection of the two planes.
- In each plane, draw a line perpendicular to the line of intersection, both meeting it at the same point.
- The angle between these two lines is the angle between the planes.
Theorem of three perpendiculars
If PN is perpendicular to a plane, and NM (in the plane) is perpendicular to a line ℓ in the plane, then PM is also perpendicular to ℓ.
Why it helps: it tells you which line in the sloping plane is perpendicular to the line of intersection, so you can find the angle between planes with a right triangle.
Solve any 3-D problem
- Pull out flat triangles. Redraw each triangle you need as a 2-D sketch, with its right angles marked.
- Work from the triangle with the most information.
- Use Pythagoras or right-triangle trig where there is a right angle; the sine or cosine formula where there isn't.
- Keep full calculator values until the end.
Worked examples
projection of G on the base is C, so the angle is ∠GAC
AC = √(8² + 6²) = 10
tan ∠GAC = GC / AC = 5/10
∠GAC ≈ 26.6°line of intersection: AB
in the base, BC ⊥ AB
GC ⊥ base and BC ⊥ AB, so GB ⊥ AB (three perpendiculars)
the angle is ∠GBC
tan ∠GBC = 5/6
∠GBC ≈ 39.8°pull out △PNA (right angle at N): PN = 20 tan 30° ≈ 11.547 m
pull out △ANB (right angle at N, south ⊥ east): AB = √(20² + 15²) = 25 m
pull out △PNB (right angle at N): tan θ = PN/NB = 11.547/15
θ ≈ 37.6°
Keep 11.547 (not 11.5) in the calculator for the last step.
Common mistakes
- Taking any angle at the point of intersection as the angle with a plane, instead of the angle with the projection.
- For two planes, using lines that are not both perpendicular to the line of intersection, or that meet it at different points.
- Assuming an angle is 90° because it "looks right" in a 3-D drawing.
- Rounding a side to 3 significant figures and then using it again.
How the DSE tests it
- Section B: a long question built on a solid (often a pyramid, prism or folded paper), with parts asking for a length, an angle between a line and a plane, then an angle between planes or "is the angle increasing?".
- Paper 2 Section B: identify the angle between a line and a plane, or between two planes, in a diagram.
Questions you might not ask in class
I can't see the 3-D picture. Is something wrong with me?
No. Almost everyone finds this hard on paper. Rotate the model, and always pull the triangle out into 2-D.
How do I know which right angle to use?
Look for a line that is vertical (perpendicular to the base): every line in the base through its foot meets it at 90°.
Is the 'angle between two planes' formula from YouTube allowed?
A shortcut may help check answers, but exam markers expect the standard method: name the angle, then calculate it. Show the standard working.