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Trigonometry in 3-D・Form 5 maths・Non-foundation topic

Angle between two planes

A standard method from Trigonometry in 3-D: the steps and worked examples.

Steps

  1. Find the line of intersection of the two planes.
  2. In each plane, draw a line perpendicular to the line of intersection, both meeting it at the same point.
  3. The angle between these two lines is the angle between the planes.

Worked examples

Example 1: Angle between a line and a plane: a cuboid ABCDEFGH has base ABCD with AB = 8 cm and BC = 6 cm; E, F, G, H are above A, B, C, D, and the height is 5 cm. Find the angle between the diagonal AG and the base.
projection of G on the base is C, so the angle is ∠GAC
AC = √(8² + 6²) = 10
tan ∠GAC = GC / AC = 5/10
∠GAC ≈ 26.6°
Example 2: Angle between two planes (theorem of three perpendiculars): in the same cuboid, find the angle between the plane ABGH and the base.
line of intersection: AB
in the base, BC ⊥ AB
GC ⊥ base and BC ⊥ AB, so GB ⊥ AB   (three perpendiculars)
the angle is ∠GBC
tan ∠GBC = 5/6
∠GBC ≈ 39.8°

For the whole topic, read Trigonometry in 3-D: key points, common mistakes and how the DSE tests it.

Other methods in this topic